Quoting professor :

When using Gimp interactively, I can assign names to the different layers, e.g. "p1", "p2", "p3" etc.

Now, is it possible to set a layer active by referring to its name? E.g.:

gimp-image-set-active-layer "p1" ?

You will have to manually search the list of layers for the one with the matching name.

The following function will do so for a given image, returning the layerID (or "0" if not found).

(define (find-layer-by-name image s) (let* (
(layer's (vector->list (cadr (gimp-image-get-layers image)))) (found 0)
)
(while (pair? layer's)
(if (string=? s (car (gimp-layer-get-name (car layer's)))) (set! found (car layer's))
)
(set! layer's (cdr layer's))
)
found
)
)

On Thursday 20 August 2009, saulgoode@flashingtwelve.brickfilms.com wrote:

Quoting professor :

When using Gimp interactively, I can assign names to the different layers, e.g. "p1", "p2", "p3" etc.

Now, is it possible to set a layer active by referring to its name? E.g.:

gimp-image-set-active-layer "p1" ?

You will have to manually search the list of layers for the one with the matching name.

The following function will do so for a given image, returning the layerID (or "0" if not found).

(define (find-layer-by-name image s) (let* (
(layer's (vector->list (cadr (gimp-image-get-layers image)))) (found 0)
)
(while (pair? layer's)
(if (string=? s (car (gimp-layer-get-name (car layer's)))) (set! found (car layer's))
)
(set! layer's (cdr layer's))
)
found
)
)

Huh???ah, You mean:

def find_layer_by_name (image, name): for layer in image:
if layer.name == name:
return layer
return None

(yes, this is the actual python code for it, not pseudo-code) you just need a proper register call to have it as a gimp-plugin

Scheme was great for its time - when computers could not hold interpreters mroe complex than what is needed to handle scheme. Scheme may still be usefull -and look great - for people who already hae it flowing in their veins. But the truth is that for very single problems one have to go through a lot of work around to get to the core of it. One of the ideas of Python, as a very high level language is not to stay between you and the problem, as you can see by the snippet above.

js
->

Sorry -- there was an error in my python function

On Wednesday 26 August 2009, Joao S. O. Bueno wrote:

Huh???ah, You mean:

def find_layer_by_name (image, name):

-> for layer in image:
+ for layer in image.layers:

if layer.name == name:
return layer
return None

That is the correct version.

js
->